1225425110433 has 4 divisors (see below), whose sum is σ = 1633900147248. Its totient is φ = 816950073620.

The previous prime is 1225425110411. The next prime is 1225425110443. The reversal of 1225425110433 is 3340115245221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1225425110433 - 2⁶ = 1225425110369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1225425110394 and 1225425110403.

It is not an unprimeable number, because it can be changed into a prime (1225425110443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 204237518403 + ... + 204237518408.

It is an arithmetic number, because the mean of its divisors is an integer number (408475036812).

Almost surely, 2^{1225425110433} is an apocalyptic number.

It is an amenable number.

1225425110433 is a deficient number, since it is larger than the sum of its proper divisors (408475036815).

1225425110433 is an equidigital number, since it uses as much as digits as its factorization.

1225425110433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 408475036814.

The product of its (nonzero) digits is 28800, while the sum is 33.

The spelling of 1225425110433 in words is "one trillion, two hundred twenty-five billion, four hundred twenty-five million, one hundred ten thousand, four hundred thirty-three".