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122542540051 = 311299393649
BaseRepresentation
bin111001000100000011…
…0101100010100010011
3102201022012102000202111
41302020012230110103
54001431342240201
6132143435530151
711565501255421
oct1621006542423
9381265360674
10122542540051
1147a74084098
121b8bb2b9957
13b72bb8c539
145d06cac111
1532c32d5b51
hex1c881ac513

122542540051 has 4 divisors (see below), whose sum is σ = 122543245000. Its totient is φ = 122541835104.

The previous prime is 122542540009. The next prime is 122542540063. The reversal of 122542540051 is 150045245221.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 122542540051 - 27 = 122542539923 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 122542539995 and 122542540022.

It is not an unprimeable number, because it can be changed into a prime (122542540451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114475 + ... + 508123.

It is an arithmetic number, because the mean of its divisors is an integer number (30635811250).

Almost surely, 2122542540051 is an apocalyptic number.

122542540051 is a deficient number, since it is larger than the sum of its proper divisors (704949).

122542540051 is an equidigital number, since it uses as much as digits as its factorization.

122542540051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 704948.

The product of its (nonzero) digits is 16000, while the sum is 31.

Adding to 122542540051 its reverse (150045245221), we get a palindrome (272587785272).

The spelling of 122542540051 in words is "one hundred twenty-two billion, five hundred forty-two million, five hundred forty thousand, fifty-one".

Divisors: 1 311299 393649 122542540051