Base | Representation |
---|---|
bin | 10001110101101100001… |
… | …111001111001011001011 |
3 | 11100012012210112021110211 |
4 | 101311230033033023023 |
5 | 130041101143104003 |
6 | 2335055013221551 |
7 | 154365326532505 |
oct | 21655417171313 |
9 | 4305183467424 |
10 | 1225881613003 |
11 | 432991237003 |
12 | 1797013318b7 |
13 | 8b7a567a708 |
14 | 43493a02d75 |
15 | 21d4bea696d |
hex | 11d6c3cf2cb |
1225881613003 has 4 divisors (see below), whose sum is σ = 1254390487768. Its totient is φ = 1197372738240.
The previous prime is 1225881612983. The next prime is 1225881613171. The reversal of 1225881613003 is 3003161885221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1225881613003 - 229 = 1225344742091 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1225881613403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14254437318 + ... + 14254437403.
It is an arithmetic number, because the mean of its divisors is an integer number (313597621942).
Almost surely, 21225881613003 is an apocalyptic number.
1225881613003 is a deficient number, since it is larger than the sum of its proper divisors (28508874765).
1225881613003 is an equidigital number, since it uses as much as digits as its factorization.
1225881613003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28508874764.
The product of its (nonzero) digits is 69120, while the sum is 40.
The spelling of 1225881613003 in words is "one trillion, two hundred twenty-five billion, eight hundred eighty-one million, six hundred thirteen thousand, three".
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