Base | Representation |
---|---|
bin | 1011001001101101000001… |
… | …1011100010010011100011 |
3 | 1121102011122102020112220210 |
4 | 2302123100123202103203 |
5 | 3101342202341321430 |
6 | 42024440122505203 |
7 | 2403565163325060 |
oct | 262332033422343 |
9 | 47364572215823 |
10 | 12261333542115 |
11 | 39a800314aa89 |
12 | 14603b3965203 |
13 | 6ac3148191c8 |
14 | 3056476c5c67 |
15 | 163e2ac112b0 |
hex | b26d06e24e3 |
12261333542115 has 16 divisors (see below), whose sum is σ = 22420724191488. Its totient is φ = 5605181047776.
The previous prime is 12261333542093. The next prime is 12261333542189. The reversal of 12261333542115 is 51124533316221.
It is a de Polignac number, because none of the positive numbers 2k-12261333542115 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 58387302477 + ... + 58387302686.
It is an arithmetic number, because the mean of its divisors is an integer number (1401295261968).
Almost surely, 212261333542115 is an apocalyptic number.
12261333542115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12261333542115 is a deficient number, since it is larger than the sum of its proper divisors (10159390649373).
12261333542115 is a wasteful number, since it uses less digits than its factorization.
12261333542115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 116774605178.
The product of its digits is 129600, while the sum is 39.
Adding to 12261333542115 its reverse (51124533316221), we get a palindrome (63385866858336).
The spelling of 12261333542115 in words is "twelve trillion, two hundred sixty-one billion, three hundred thirty-three million, five hundred forty-two thousand, one hundred fifteen".
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