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12300012115 = 522311031401
BaseRepresentation
bin10110111010010001…
…10100101001010011
31011202012122100121021
423131020310221103
5200142300341430
65352303540311
7613543243426
oct133510645123
934665570537
1012300012115
115242044176
1224732ba697
131210367ca1
148497d59bd
154bec8307a
hex2dd234a53

12300012115 has 8 divisors (see below), whose sum is σ = 14826204288. Its totient is φ = 9795883200.

The previous prime is 12300012113. The next prime is 12300012119. The reversal of 12300012115 is 51121000321.

12300012115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12300012115 - 21 = 12300012113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12300012113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5514586 + ... + 5516815.

It is an arithmetic number, because the mean of its divisors is an integer number (1853275536).

Almost surely, 212300012115 is an apocalyptic number.

12300012115 is a deficient number, since it is larger than the sum of its proper divisors (2526192173).

12300012115 is a wasteful number, since it uses less digits than its factorization.

12300012115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11031629.

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 12300012115 its reverse (51121000321), we get a palindrome (63421012436).

The spelling of 12300012115 in words is "twelve billion, three hundred million, twelve thousand, one hundred fifteen".

Divisors: 1 5 223 1115 11031401 55157005 2460002423 12300012115