Base | Representation |
---|---|
bin | 10110111010010001… |
… | …11001010000011011 |
3 | 1011202012200022111211 |
4 | 23131020321100123 |
5 | 200142301443003 |
6 | 5352304203551 |
7 | 613543352461 |
oct | 133510712033 |
9 | 34665608454 |
10 | 12300031003 |
11 | 5242057387 |
12 | 24733095b7 |
13 | 1210373770 |
14 | 8497dc831 |
15 | 4bec8896d |
hex | 2dd23941b |
12300031003 has 8 divisors (see below), whose sum is σ = 13320190800. Its totient is φ = 11290443168.
The previous prime is 12300030997. The next prime is 12300031039. The reversal of 12300031003 is 30013000321.
12300031003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12300031003 is a prime.
It is a super-3 number, since 3×123000310033 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (13).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12300041003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2640568 + ... + 2645221.
It is an arithmetic number, because the mean of its divisors is an integer number (1665023850).
Almost surely, 212300031003 is an apocalyptic number.
12300031003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12300031003 is a deficient number, since it is larger than the sum of its proper divisors (1020159797).
12300031003 is a wasteful number, since it uses less digits than its factorization.
12300031003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5285981.
The product of its (nonzero) digits is 54, while the sum is 13.
Adding to 12300031003 its reverse (30013000321), we get a palindrome (42313031324).
The spelling of 12300031003 in words is "twelve billion, three hundred million, thirty-one thousand, three".
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