Base | Representation |
---|---|
bin | 10110111010010011… |
… | …11011110001001001 |
3 | 1011202020012011012211 |
4 | 23131021323301021 |
5 | 200142334202213 |
6 | 5352314105121 |
7 | 613545565645 |
oct | 133511736111 |
9 | 34666164184 |
10 | 12300303433 |
11 | 5242223030 |
12 | 247341b1a1 |
13 | 121043a772 |
14 | 84986dc25 |
15 | 4becde53d |
hex | 2dd27bc49 |
12300303433 has 4 divisors (see below), whose sum is σ = 13418512848. Its totient is φ = 11182094020.
The previous prime is 12300303427. The next prime is 12300303479. The reversal of 12300303433 is 33430300321.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12300303433 - 221 = 12298206281 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12300303133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 559104691 + ... + 559104712.
It is an arithmetic number, because the mean of its divisors is an integer number (3354628212).
Almost surely, 212300303433 is an apocalyptic number.
It is an amenable number.
12300303433 is a deficient number, since it is larger than the sum of its proper divisors (1118209415).
12300303433 is a wasteful number, since it uses less digits than its factorization.
12300303433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1118209414.
The product of its (nonzero) digits is 1944, while the sum is 22.
Adding to 12300303433 its reverse (33430300321), we get a palindrome (45730603754).
The spelling of 12300303433 in words is "twelve billion, three hundred million, three hundred three thousand, four hundred thirty-three".
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