Base | Representation |
---|---|
bin | 11011111110000010010001… |
… | …010000001111001100111011 |
3 | 121010112200002022220021211210 |
4 | 123332002101100033030323 |
5 | 112110400043334412311 |
6 | 1113342052443454203 |
7 | 34624125625504440 |
oct | 3376022120171473 |
9 | 533480068807753 |
10 | 123010300310331 |
11 | 36216414720555 |
12 | 11968278827363 |
13 | 5383a8ac23155 |
14 | 2253a31d3d9c7 |
15 | e34ba82c83a6 |
hex | 6fe09140f33b |
123010300310331 has 8 divisors (see below), whose sum is σ = 187444267139584. Its totient is φ = 70291600177320.
The previous prime is 123010300310269. The next prime is 123010300310353. The reversal of 123010300310331 is 133013003010321.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 123010300310331 - 229 = 123009763439419 is a prime.
It is a super-2 number, since 2×1230103003103312 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21), and also a Moran number because the ratio is a prime number: 5857633348111 = 123010300310331 / (1 + 2 + 3 + 0 + 1 + 0 + 3 + 0 + 0 + 3 + 1 + 0 + 3 + 3 + 1).
It is a junction number, because it is equal to n+sod(n) for n = 123010300310298 and 123010300310307.
It is not an unprimeable number, because it can be changed into a prime (123010300310531) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2928816674035 + ... + 2928816674076.
It is an arithmetic number, because the mean of its divisors is an integer number (23430533392448).
Almost surely, 2123010300310331 is an apocalyptic number.
123010300310331 is a deficient number, since it is larger than the sum of its proper divisors (64433966829253).
123010300310331 is an equidigital number, since it uses as much as digits as its factorization.
123010300310331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5857633348121.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 123010300310331 its reverse (133013003010321), we get a palindrome (256023303320652).
The spelling of 123010300310331 in words is "one hundred twenty-three trillion, ten billion, three hundred million, three hundred ten thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •