Base | Representation |
---|---|
bin | 10110111010011010… |
… | …00110010011001011 |
3 | 1011202021202022011122 |
4 | 23131031012103023 |
5 | 200143042224003 |
6 | 5352343545455 |
7 | 613555622345 |
oct | 133515062313 |
9 | 34667668148 |
10 | 12301133003 |
11 | 524273a325 |
12 | 247375b28b |
13 | 121066b233 |
14 | 849a08295 |
15 | 4bee05238 |
hex | 2dd3464cb |
12301133003 has 4 divisors (see below), whose sum is σ = 13024729080. Its totient is φ = 11577536928.
The previous prime is 12301132999. The next prime is 12301133021. The reversal of 12301133003 is 30033110321.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 12301133003 - 22 = 12301132999 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (17), and also a Moran number because the ratio is a prime number: 723596059 = 12301133003 / (1 + 2 + 3 + 0 + 1 + 1 + 3 + 3 + 0 + 0 + 3).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12301133063) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 361798013 + ... + 361798046.
It is an arithmetic number, because the mean of its divisors is an integer number (3256182270).
Almost surely, 212301133003 is an apocalyptic number.
12301133003 is a deficient number, since it is larger than the sum of its proper divisors (723596077).
12301133003 is an equidigital number, since it uses as much as digits as its factorization.
12301133003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 723596076.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 12301133003 its reverse (30033110321), we get a palindrome (42334243324).
The spelling of 12301133003 in words is "twelve billion, three hundred one million, one hundred thirty-three thousand, three".
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