Base | Representation |
---|---|
bin | 11011111110000100111111… |
… | …010010110001010101010011 |
3 | 121010112221121211012120012002 |
4 | 123332010333102301111103 |
5 | 112110422033333210003 |
6 | 1113343254311224215 |
7 | 34624261162315454 |
oct | 3376047722612523 |
9 | 533487554176162 |
10 | 123013220210003 |
11 | 36217682951382 |
12 | 1196895267806b |
13 | 5384134b40736 |
14 | 2253c2ba5512b |
15 | e34cc97e8a88 |
hex | 6fe13f4b1553 |
123013220210003 has 4 divisors (see below), whose sum is σ = 130249291987080. Its totient is φ = 115777148432928.
The previous prime is 123013220209961. The next prime is 123013220210011. The reversal of 123013220210003 is 300012022310321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 123013220210003 - 210 = 123013220208979 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (123013220210093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3618035888513 + ... + 3618035888546.
It is an arithmetic number, because the mean of its divisors is an integer number (32562322996770).
Almost surely, 2123013220210003 is an apocalyptic number.
123013220210003 is a deficient number, since it is larger than the sum of its proper divisors (7236071777077).
123013220210003 is an equidigital number, since it uses as much as digits as its factorization.
123013220210003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7236071777076.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 123013220210003 its reverse (300012022310321), we get a palindrome (423025242520324).
The spelling of 123013220210003 in words is "one hundred twenty-three trillion, thirteen billion, two hundred twenty million, two hundred ten thousand, three".
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