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123014114433 = 3271952604991
BaseRepresentation
bin111001010010000110…
…1100110110010000001
3102202112001202111012100
41302210031212302001
54003413103130213
6132302323221013
711613255502020
oct1624415466201
9382461674170
10123014114433
1148196295991
121ba11217769
13b7a57a1132
145d4d7848b7
1532ee8d6773
hex1ca4366c81

123014114433 has 12 divisors (see below), whose sum is σ = 203070919168. Its totient is φ = 70293779640.

The previous prime is 123014114407. The next prime is 123014114441. The reversal of 123014114433 is 334411410321.

It is not a de Polignac number, because 123014114433 - 216 = 123014048897 is a prime.

It is a super-2 number, since 2×1230141144332 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 123014114397 and 123014114406.

It is not an unprimeable number, because it can be changed into a prime (123014124433) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 976302433 + ... + 976302558.

Almost surely, 2123014114433 is an apocalyptic number.

It is an amenable number.

123014114433 is a deficient number, since it is larger than the sum of its proper divisors (80056804735).

123014114433 is a wasteful number, since it uses less digits than its factorization.

123014114433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1952605004 (or 1952605001 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 123014114433 its reverse (334411410321), we get a palindrome (457425524754).

The spelling of 123014114433 in words is "one hundred twenty-three billion, fourteen million, one hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 3 7 9 21 63 1952604991 5857814973 13668234937 17573444919 41004704811 123014114433