123030131113 has 4 divisors (see below), whose sum is σ = 123031608448. Its totient is φ = 123028653780.

The previous prime is 123030131111. The next prime is 123030131143. The reversal of 123030131113 is 311131030321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311131030321 = 17 ⋅18301825313.

It is a cyclic number.

It is not a de Polignac number, because 123030131113 - 2¹ = 123030131111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (123030131111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 605781 + ... + 782962.

It is an arithmetic number, because the mean of its divisors is an integer number (30757902112).

Almost surely, 2^123030131113 is an apocalyptic number.

It is an amenable number.

123030131113 is a deficient number, since it is larger than the sum of its proper divisors (1477335).

123030131113 is an equidigital number, since it uses as much as digits as its factorization.

123030131113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1477334.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 123030131113 its reverse (311131030321), we get a palindrome (434161161434).

The spelling of 123030131113 in words is "one hundred twenty-three billion, thirty million, one hundred thirty-one thousand, one hundred thirteen".