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12303103001113 = 61527273825179
BaseRepresentation
bin1011001100001000101000…
…0101011000001000011001
31121120011110101211220211201
42303002022011120020121
53103033223332013423
642055544551154201
72406604235012341
oct263021205301031
947504411756751
1012303103001113
113a137979a2831
121468510375961
136b3240357512
1430768ac99d21
15165072c1c2ad
hexb308a158219

12303103001113 has 8 divisors (see below), whose sum is σ = 12505033644480. Its totient is φ = 12101180113680.

The previous prime is 12303103001087. The next prime is 12303103001141. The reversal of 12303103001113 is 31110030130321.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12303103001113 - 217 = 12303102870041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12303103001183) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1303758 + ... + 5128936.

It is an arithmetic number, because the mean of its divisors is an integer number (1563129205560).

Almost surely, 212303103001113 is an apocalyptic number.

It is an amenable number.

12303103001113 is a deficient number, since it is larger than the sum of its proper divisors (201930643367).

12303103001113 is an equidigital number, since it uses as much as digits as its factorization.

12303103001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3877967.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 12303103001113 its reverse (31110030130321), we get a palindrome (43413133131434).

The spelling of 12303103001113 in words is "twelve trillion, three hundred three billion, one hundred three million, one thousand, one hundred thirteen".

Divisors: 1 61 52727 3216347 3825179 233335919 201690213133 12303103001113