Base | Representation |
---|---|
bin | 10001111001110100010… |
… | …001001110101000111011 |
3 | 11100121122111210201021111 |
4 | 101321310101032220323 |
5 | 130124134144220443 |
6 | 2341110333221151 |
7 | 154613155446514 |
oct | 21716421165073 |
9 | 4317574721244 |
10 | 1230311320123 |
11 | 434854736586 |
12 | 17a5389317b7 |
13 | 8c0303122a2 |
14 | 43794051a0b |
15 | 2200ad0c69d |
hex | 11e7444ea3b |
1230311320123 has 4 divisors (see below), whose sum is σ = 1231928024328. Its totient is φ = 1228694615920.
The previous prime is 1230311320103. The next prime is 1230311320157. The reversal of 1230311320123 is 3210231130321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1230311320123 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1230311320094 and 1230311320103.
It is not an unprimeable number, because it can be changed into a prime (1230311320103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808350961 + ... + 808352482.
It is an arithmetic number, because the mean of its divisors is an integer number (307982006082).
Almost surely, 21230311320123 is an apocalyptic number.
1230311320123 is a deficient number, since it is larger than the sum of its proper divisors (1616704205).
1230311320123 is an equidigital number, since it uses as much as digits as its factorization.
1230311320123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1616704204.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1230311320123 its reverse (3210231130321), we get a palindrome (4440542450444).
The spelling of 1230311320123 in words is "one trillion, two hundred thirty billion, three hundred eleven million, three hundred twenty thousand, one hundred twenty-three".
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