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123042131651 = 314999793979
BaseRepresentation
bin111001010010111100…
…0011110111011000011
3102202121000110220121002
41302211320132323003
54003442241203101
6132305203522215
711614045601615
oct1624570367303
9382530426532
10123042131651
114820009170a
121ba1a68936b
13b7ab53077a
145d53398db5
1533020bcd6b
hex1ca5e1eec3

123042131651 has 8 divisors (see below), whose sum is σ = 127036800000. Its totient is φ = 119049061320.

The previous prime is 123042131647. The next prime is 123042131657. The reversal of 123042131651 is 156131240321.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 123042131651 - 22 = 123042131647 is a prime.

It is a super-2 number, since 2×1230421316512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (123042131657) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 242021 + ... + 551958.

It is an arithmetic number, because the mean of its divisors is an integer number (15879600000).

Almost surely, 2123042131651 is an apocalyptic number.

123042131651 is a deficient number, since it is larger than the sum of its proper divisors (3994668349).

123042131651 is an equidigital number, since it uses as much as digits as its factorization.

123042131651 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 799009.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 123042131651 its reverse (156131240321), we get a palindrome (279173371972).

The spelling of 123042131651 in words is "one hundred twenty-three billion, forty-two million, one hundred thirty-one thousand, six hundred fifty-one".

Divisors: 1 31 4999 154969 793979 24613349 3969101021 123042131651