12304404131 has 4 divisors (see below), whose sum is σ = 12636955632. Its totient is φ = 11971852632.

The previous prime is 12304404107. The next prime is 12304404169. The reversal of 12304404131 is 13140440321.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13140440321 = 3673 ⋅3577577.

It is a cyclic number.

It is not a de Polignac number, because 12304404131 - 2¹⁰ = 12304403107 is a prime.

It is a super-2 number, since 2×12304404131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12304404097 and 12304404106.

It is not an unprimeable number, because it can be changed into a prime (12304004131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166275695 + ... + 166275768.

It is an arithmetic number, because the mean of its divisors is an integer number (3159238908).

Almost surely, 2^12304404131 is an apocalyptic number.

12304404131 is a deficient number, since it is larger than the sum of its proper divisors (332551501).

12304404131 is an equidigital number, since it uses as much as digits as its factorization.

12304404131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 332551500.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12304404131 its reverse (13140440321), we get a palindrome (25444844452).

The spelling of 12304404131 in words is "twelve billion, three hundred four million, four hundred four thousand, one hundred thirty-one".