Base | Representation |
---|---|
bin | 11011111110100010110111… |
… | …100001110110011101011011 |
3 | 121010200000102200010112010120 |
4 | 123332202313201312131123 |
5 | 112111433234330401110 |
6 | 1113410121555444323 |
7 | 34626505202611446 |
oct | 3376426741663533 |
9 | 533600380115116 |
10 | 123045302200155 |
11 | 3622a246342425 |
12 | 119730068b66a3 |
13 | 538717865906a |
14 | 22555d27bc65d |
15 | e35a560cd870 |
hex | 6fe8b787675b |
123045302200155 has 16 divisors (see below), whose sum is σ = 199084533899040. Its totient is φ = 64886811047168.
The previous prime is 123045302200129. The next prime is 123045302200187. The reversal of 123045302200155 is 551002203540321.
It is a cyclic number.
It is not a de Polignac number, because 123045302200155 - 25 = 123045302200123 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 46084381512 + ... + 46084384181.
It is an arithmetic number, because the mean of its divisors is an integer number (12442783368690).
Almost surely, 2123045302200155 is an apocalyptic number.
123045302200155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
123045302200155 is a deficient number, since it is larger than the sum of its proper divisors (76039231698885).
123045302200155 is an equidigital number, since it uses as much as digits as its factorization.
123045302200155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 92168765790.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 123045302200155 its reverse (551002203540321), we get a palindrome (674047505740476).
The spelling of 123045302200155 in words is "one hundred twenty-three trillion, forty-five billion, three hundred two million, two hundred thousand, one hundred fifty-five".
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