Search a number
-
+
123050012403 = 346798766119
BaseRepresentation
bin111001010011001011…
…0100010111011110011
3102202121120022021221210
41302212112202323303
54004001300344103
6132310044451203
711614202563563
oct1624626427363
9382546267853
10123050012403
114820458462a
121ba21249b03
13b7b005c836
145d5444ada3
153302b27e03
hex1ca65a2ef3

123050012403 has 8 divisors (see below), whose sum is σ = 164101766400. Its totient is φ = 82015800008.

The previous prime is 123050012399. The next prime is 123050012431. The reversal of 123050012403 is 304210050321.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 123050012403 - 22 = 123050012399 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 123050012403.

It is not an unprimeable number, because it can be changed into a prime (123050012453) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4369023 + ... + 4397096.

It is an arithmetic number, because the mean of its divisors is an integer number (20512720800).

Almost surely, 2123050012403 is an apocalyptic number.

123050012403 is a deficient number, since it is larger than the sum of its proper divisors (41051753997).

123050012403 is an equidigital number, since it uses as much as digits as its factorization.

123050012403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8770801.

The product of its (nonzero) digits is 720, while the sum is 21.

Adding to 123050012403 its reverse (304210050321), we get a palindrome (427260062724).

The spelling of 123050012403 in words is "one hundred twenty-three billion, fifty million, twelve thousand, four hundred three".

Divisors: 1 3 4679 14037 8766119 26298357 41016670801 123050012403