Base | Representation |
---|---|
bin | 10001111010000000001… |
… | …011011010010000100011 |
3 | 11100122011102202200011101 |
4 | 101322000023122100203 |
5 | 130130041321341233 |
6 | 2341142231455231 |
7 | 154621132645612 |
oct | 21720013322043 |
9 | 4318142680141 |
10 | 1230511121443 |
11 | 4349474a323a |
12 | 17a593827517 |
13 | 8c06282a016 |
14 | 437b27c1879 |
15 | 2201d627c7d |
hex | 11e802da423 |
1230511121443 has 4 divisors (see below), whose sum is σ = 1284011605008. Its totient is φ = 1177010637880.
The previous prime is 1230511121429. The next prime is 1230511121447. The reversal of 1230511121443 is 3441211150321.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-1230511121443 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1230511121447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26750241748 + ... + 26750241793.
It is an arithmetic number, because the mean of its divisors is an integer number (321002901252).
Almost surely, 21230511121443 is an apocalyptic number.
1230511121443 is a deficient number, since it is larger than the sum of its proper divisors (53500483565).
1230511121443 is an equidigital number, since it uses as much as digits as its factorization.
1230511121443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53500483564.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 1230511121443 its reverse (3441211150321), we get a palindrome (4671722271764).
The spelling of 1230511121443 in words is "one trillion, two hundred thirty billion, five hundred eleven million, one hundred twenty-one thousand, four hundred forty-three".
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