Base | Representation |
---|---|
bin | 11011111110101011111011… |
… | …101010000110111010110001 |
3 | 121010200221112222101121022111 |
4 | 123332223323222012322301 |
5 | 112112113202444300001 |
6 | 1113414411442405321 |
7 | 34630301325406513 |
oct | 3376537352067261 |
9 | 533627488347274 |
10 | 123055035150001 |
11 | 36233390338729 |
12 | 11974a82360841 |
13 | 5388069c14296 |
14 | 2255c772a7bb3 |
15 | e35e257da851 |
hex | 6feafba86eb1 |
123055035150001 has 4 divisors (see below), whose sum is σ = 123056265911104. Its totient is φ = 123053804388900.
The previous prime is 123055035149989. The next prime is 123055035150023. The reversal of 123055035150001 is 100051530550321.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 123055035150001 - 27 = 123055035149873 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (123055035151001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 615230565 + ... + 615430546.
It is an arithmetic number, because the mean of its divisors is an integer number (30764066477776).
Almost surely, 2123055035150001 is an apocalyptic number.
It is an amenable number.
123055035150001 is a deficient number, since it is larger than the sum of its proper divisors (1230761103).
123055035150001 is an equidigital number, since it uses as much as digits as its factorization.
123055035150001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1230761102.
The product of its (nonzero) digits is 11250, while the sum is 31.
The spelling of 123055035150001 in words is "one hundred twenty-three trillion, fifty-five billion, thirty-five million, one hundred fifty thousand, one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •