Base | Representation |
---|---|
bin | 10110111010111011… |
… | …10001100111110001 |
3 | 1011202120222102002022 |
4 | 23131131301213301 |
5 | 200200202123003 |
6 | 5353021401225 |
7 | 613641031103 |
oct | 133535614761 |
9 | 34676872068 |
10 | 12305504753 |
11 | 5245155943 |
12 | 2475109215 |
13 | 121153c079 |
14 | 84a425573 |
15 | 4c04ba738 |
hex | 2dd7719f1 |
12305504753 has 4 divisors (see below), whose sum is σ = 12314129520. Its totient is φ = 12296879988.
The previous prime is 12305504711. The next prime is 12305504773. The reversal of 12305504753 is 35740550321.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12305504753 - 212 = 12305500657 is a prime.
It is a super-2 number, since 2×123055047532 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12305504773) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4310243 + ... + 4313096.
It is an arithmetic number, because the mean of its divisors is an integer number (3078532380).
Almost surely, 212305504753 is an apocalyptic number.
It is an amenable number.
12305504753 is a deficient number, since it is larger than the sum of its proper divisors (8624767).
12305504753 is an equidigital number, since it uses as much as digits as its factorization.
12305504753 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8624766.
The product of its (nonzero) digits is 63000, while the sum is 35.
The spelling of 12305504753 in words is "twelve billion, three hundred five million, five hundred four thousand, seven hundred fifty-three".
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