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12310000113 = 34103333371
BaseRepresentation
bin10110111011011101…
…11011000111110001
31011202220102210120010
423131232323013301
5200202330000423
65353302005133
7614024163105
oct133556730761
934686383503
1012310000113
115247746314
1224767167a9
131212454248
1484ac75905
154c0aa7693
hex2ddbbb1f1

12310000113 has 4 divisors (see below), whose sum is σ = 16413333488. Its totient is φ = 8206666740.

The previous prime is 12310000097. The next prime is 12310000133. The reversal of 12310000113 is 31100001321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12310000113 - 24 = 12310000097 is a prime.

It is a super-2 number, since 2×123100001132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12310000133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2051666683 + ... + 2051666688.

It is an arithmetic number, because the mean of its divisors is an integer number (4103333372).

Almost surely, 212310000113 is an apocalyptic number.

It is an amenable number.

12310000113 is a deficient number, since it is larger than the sum of its proper divisors (4103333375).

12310000113 is an equidigital number, since it uses as much as digits as its factorization.

12310000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4103333374.

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 12310000113 its reverse (31100001321), we get a palindrome (43410001434).

The spelling of 12310000113 in words is "twelve billion, three hundred ten million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 3 4103333371 12310000113