Base | Representation |
---|---|
bin | 10001111010101111001… |
… | …101100000101110111011 |
3 | 11100201012102120002101002 |
4 | 101322233031200232323 |
5 | 130133200322421103 |
6 | 2341352420315215 |
7 | 154646524011356 |
oct | 21725715405673 |
9 | 4321172502332 |
10 | 1231300201403 |
11 | 435211955738 |
12 | 17a773b42b0b |
13 | 8c15a15863c |
14 | 4384950729d |
15 | 22067a44488 |
hex | 11eaf360bbb |
1231300201403 has 8 divisors (see below), whose sum is σ = 1243526138256. Its totient is φ = 1219074948000.
The previous prime is 1231300201343. The next prime is 1231300201433. The reversal of 1231300201403 is 3041020031321.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1231300201403 - 210 = 1231300200379 is a prime.
It is a super-2 number, since 2×12313002014032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1231300201433) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3938213 + ... + 4239353.
It is an arithmetic number, because the mean of its divisors is an integer number (155440767282).
Almost surely, 21231300201403 is an apocalyptic number.
1231300201403 is a deficient number, since it is larger than the sum of its proper divisors (12225936853).
1231300201403 is a wasteful number, since it uses less digits than its factorization.
1231300201403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 341725.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1231300201403 its reverse (3041020031321), we get a palindrome (4272320232724).
The spelling of 1231300201403 in words is "one trillion, two hundred thirty-one billion, three hundred million, two hundred one thousand, four hundred three".
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