Base | Representation |
---|---|
bin | 10001111010101111010… |
… | …000100100000010111011 |
3 | 11100201012111001201202201 |
4 | 101322233100210002323 |
5 | 130133201024021103 |
6 | 2341352445411031 |
7 | 154646533552624 |
oct | 21725720440273 |
9 | 4321174051681 |
10 | 1231301001403 |
11 | 4352123517a0 |
12 | 17a774269a77 |
13 | 8c15a378805 |
14 | 43849674a4b |
15 | 22067b5151d |
hex | 11eaf4240bb |
1231301001403 has 4 divisors (see below), whose sum is σ = 1343237456088. Its totient is φ = 1119364546720.
The previous prime is 1231301001383. The next prime is 1231301001421. The reversal of 1231301001403 is 3041001031321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1231301001403 is a prime.
It is a super-2 number, since 2×12313010014032 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1231301002403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55968227326 + ... + 55968227347.
It is an arithmetic number, because the mean of its divisors is an integer number (335809364022).
Almost surely, 21231301001403 is an apocalyptic number.
1231301001403 is a deficient number, since it is larger than the sum of its proper divisors (111936454685).
1231301001403 is a wasteful number, since it uses less digits than its factorization.
1231301001403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 111936454684.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 1231301001403 its reverse (3041001031321), we get a palindrome (4272302032724).
The spelling of 1231301001403 in words is "one trillion, two hundred thirty-one billion, three hundred one million, one thousand, four hundred three".
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