12313211201433 has 12 divisors (see below), whose sum is σ = 17792443469268. Its totient is φ = 8205717949440.

The previous prime is 12313211201413. The next prime is 12313211201449. The reversal of 12313211201433 is 33410211231321.

12313211201433 is a `hidden beast` number, since 1 + 2 + 3 + 1 + 3 + 21 + 1 + 201 + 433 = 666.

12313211201433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 7562324001024 + 4750887200409 = 2749968^2 + 2179653^2 .

It is not a de Polignac number, because 12313211201433 - 2⁸ = 12313211201177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12313211201397 and 12313211201406.

It is not an unprimeable number, because it can be changed into a prime (12313211201413) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 257434608 + ... + 257482433.

It is an arithmetic number, because the mean of its divisors is an integer number (1482703622439).

Almost surely, 2^{12313211201433} is an apocalyptic number.

It is an amenable number.

12313211201433 is a deficient number, since it is larger than the sum of its proper divisors (5479232267835).

12313211201433 is a wasteful number, since it uses less digits than its factorization.

12313211201433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 514919704 (or 514919701 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 12313211201433 its reverse (33410211231321), we get a palindrome (45723422432754).

The spelling of 12313211201433 in words is "twelve trillion, three hundred thirteen billion, two hundred eleven million, two hundred one thousand, four hundred thirty-three".