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1231400102243 = 1964810531697
BaseRepresentation
bin10001111010110101001…
…010100110100101100011
311100201110101112120120012
4101322311022212211203
5130133401411232433
62341410345435135
7154652146111433
oct21726512464543
94321411476505
101231400102243
11435263289713
1217a7a149baab
138c174a65c6c
14438588b02c3
15220716c9848
hex11eb52a6963

1231400102243 has 4 divisors (see below), whose sum is σ = 1296210633960. Its totient is φ = 1166589570528.

The previous prime is 1231400102213. The next prime is 1231400102291. The reversal of 1231400102243 is 3422010041321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1231400102243 - 222 = 1231395907939 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1231400102213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32405265830 + ... + 32405265867.

It is an arithmetic number, because the mean of its divisors is an integer number (324052658490).

Almost surely, 21231400102243 is an apocalyptic number.

1231400102243 is a deficient number, since it is larger than the sum of its proper divisors (64810531717).

1231400102243 is an equidigital number, since it uses as much as digits as its factorization.

1231400102243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64810531716.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1231400102243 its reverse (3422010041321), we get a palindrome (4653410143564).

The spelling of 1231400102243 in words is "one trillion, two hundred thirty-one billion, four hundred million, one hundred two thousand, two hundred forty-three".

Divisors: 1 19 64810531697 1231400102243