Base | Representation |
---|---|
bin | 111001010110000001… |
… | …0011011001111101011 |
3 | 102202212012210112221202 |
4 | 1302230002123033223 |
5 | 4004200210320243 |
6 | 132323333154415 |
7 | 11616441432440 |
oct | 1625402331753 |
9 | 382765715852 |
10 | 123145401323 |
11 | 4825340674a |
12 | 1ba4918ba0b |
13 | b7c6a4a599 |
14 | 5d62d9b9c7 |
15 | 330b1bb4b8 |
hex | 1cac09b3eb |
123145401323 has 4 divisors (see below), whose sum is σ = 140737601520. Its totient is φ = 105553201128.
The previous prime is 123145401259. The next prime is 123145401341. The reversal of 123145401323 is 323104541321.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 323104541321 = 1907 ⋅169430803.
It is a cyclic number.
It is not a de Polignac number, because 123145401323 - 26 = 123145401259 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (123145401823) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8796100088 + ... + 8796100101.
It is an arithmetic number, because the mean of its divisors is an integer number (35184400380).
Almost surely, 2123145401323 is an apocalyptic number.
123145401323 is a deficient number, since it is larger than the sum of its proper divisors (17592200197).
123145401323 is an equidigital number, since it uses as much as digits as its factorization.
123145401323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17592200196.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 123145401323 its reverse (323104541321), we get a palindrome (446249942644).
The spelling of 123145401323 in words is "one hundred twenty-three billion, one hundred forty-five million, four hundred one thousand, three hundred twenty-three".
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