Base | Representation |
---|---|
bin | 1011001100110011100110… |
… | …1111101000111110101011 |
3 | 1121121021020102210120212122 |
4 | 2303030321233220332223 |
5 | 3103230340321340223 |
6 | 42105133441501455 |
7 | 2410463155064066 |
oct | 263147157507653 |
9 | 47537212716778 |
10 | 12314640027563 |
11 | 3a18678287535 |
12 | 146a7b004188b |
13 | 6b435b5cc1a3 |
14 | 3080631dd8dd |
15 | 1654ea9da5c8 |
hex | b3339be8fab |
12314640027563 has 4 divisors (see below), whose sum is σ = 12614997101448. Its totient is φ = 12014282953680.
The previous prime is 12314640027553. The next prime is 12314640027583. The reversal of 12314640027563 is 36572004641321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12314640027563 - 232 = 12310345060267 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12314640027533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150178536881 + ... + 150178536962.
It is an arithmetic number, because the mean of its divisors is an integer number (3153749275362).
Almost surely, 212314640027563 is an apocalyptic number.
12314640027563 is a deficient number, since it is larger than the sum of its proper divisors (300357073885).
12314640027563 is an equidigital number, since it uses as much as digits as its factorization.
12314640027563 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 300357073884.
The product of its (nonzero) digits is 725760, while the sum is 44.
Adding to 12314640027563 its reverse (36572004641321), we get a palindrome (48886644668884).
The spelling of 12314640027563 in words is "twelve trillion, three hundred fourteen billion, six hundred forty million, twenty-seven thousand, five hundred sixty-three".
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