Base | Representation |
---|---|
bin | 1011001100110110011111… |
… | …0010000110101011011001 |
3 | 1121121100020021012110120011 |
4 | 2303031213302012223121 |
5 | 3103233431040103213 |
6 | 42105342233001521 |
7 | 2410521254256655 |
oct | 263154762065331 |
9 | 47540207173504 |
10 | 12315412425433 |
11 | 3a18a34285487 |
12 | 146a9868532a1 |
13 | 6b4452639650 |
14 | 3080d7a21a65 |
15 | 16554370e03d |
hex | b3367c86ad9 |
12315412425433 has 8 divisors (see below), whose sum is σ = 13262799742976. Its totient is φ = 11368031950800.
The previous prime is 12315412425373. The next prime is 12315412425499. The reversal of 12315412425433 is 33452421451321.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12315412425433 - 221 = 12315410328281 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12315412425733) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2391538 + ... + 5509108.
It is an arithmetic number, because the mean of its divisors is an integer number (1657849967872).
Almost surely, 212315412425433 is an apocalyptic number.
12315412425433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
12315412425433 is a deficient number, since it is larger than the sum of its proper divisors (947387317543).
12315412425433 is a wasteful number, since it uses less digits than its factorization.
12315412425433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3421455.
The product of its digits is 345600, while the sum is 40.
Adding to 12315412425433 its reverse (33452421451321), we get a palindrome (45767833876754).
The spelling of 12315412425433 in words is "twelve trillion, three hundred fifteen billion, four hundred twelve million, four hundred twenty-five thousand, four hundred thirty-three".
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