Base | Representation |
---|---|
bin | 1011001101001100000110… |
… | …0101011111000001010011 |
3 | 1121121220012120221201100122 |
4 | 2303103001211133001103 |
5 | 3103332321243042003 |
6 | 42112142041340455 |
7 | 2411115112160450 |
oct | 263230145370123 |
9 | 47556176851318 |
10 | 12321214034003 |
11 | 3a20441121906 |
12 | 146bb2579772b |
13 | 6b4b68592324 |
14 | 3084c834a827 |
15 | 165782c09238 |
hex | b34c195f053 |
12321214034003 has 4 divisors (see below), whose sum is σ = 14081387467440. Its totient is φ = 10561040600568.
The previous prime is 12321214033987. The next prime is 12321214034033. The reversal of 12321214034003 is 30043041212321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12321214034003 - 24 = 12321214033987 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12321214034033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 880086716708 + ... + 880086716721.
It is an arithmetic number, because the mean of its divisors is an integer number (3520346866860).
Almost surely, 212321214034003 is an apocalyptic number.
12321214034003 is a deficient number, since it is larger than the sum of its proper divisors (1760173433437).
12321214034003 is an equidigital number, since it uses as much as digits as its factorization.
12321214034003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1760173433436.
The product of its (nonzero) digits is 3456, while the sum is 26.
Adding to 12321214034003 its reverse (30043041212321), we get a palindrome (42364255246324).
The spelling of 12321214034003 in words is "twelve trillion, three hundred twenty-one billion, two hundred fourteen million, thirty-four thousand, three".
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