Base | Representation |
---|---|
bin | 10001111011100100110… |
… | …110110100000111001011 |
3 | 11100210112011002211100002 |
4 | 101323210312310013023 |
5 | 130142021224034011 |
6 | 2342022011033215 |
7 | 155011033031525 |
oct | 21734466640713 |
9 | 4323464084302 |
10 | 1232200221131 |
11 | 4356339a08a0 |
12 | 17a98543b80b |
13 | 8c27175aca9 |
14 | 438d2c6aa15 |
15 | 220bba76c3b |
hex | 11ee4db41cb |
1232200221131 has 4 divisors (see below), whose sum is σ = 1344218423064. Its totient is φ = 1120182019200.
The previous prime is 1232200221127. The next prime is 1232200221139. The reversal of 1232200221131 is 1311220022321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1232200221131 - 22 = 1232200221127 is a prime.
It is a super-2 number, since 2×12322002211312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1232200221139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56009100950 + ... + 56009100971.
It is an arithmetic number, because the mean of its divisors is an integer number (336054605766).
Almost surely, 21232200221131 is an apocalyptic number.
1232200221131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1232200221131 is a deficient number, since it is larger than the sum of its proper divisors (112018201933).
1232200221131 is a wasteful number, since it uses less digits than its factorization.
1232200221131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 112018201932.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 1232200221131 its reverse (1311220022321), we get a palindrome (2543420243452).
The spelling of 1232200221131 in words is "one trillion, two hundred thirty-two billion, two hundred million, two hundred twenty-one thousand, one hundred thirty-one".
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