Base | Representation |
---|---|
bin | 1011001101001111000100… |
… | …1110100011111100000011 |
3 | 1121121222021021222012222122 |
4 | 2303103301032203330003 |
5 | 3103340440403044303 |
6 | 42112353233154455 |
7 | 2411143656116132 |
oct | 263236116437403 |
9 | 47558237865878 |
10 | 12322013331203 |
11 | 3a20811322704 |
12 | 14701093bba2b |
13 | 6b4c6505a354 |
14 | 308562571919 |
15 | 1657cce92e38 |
hex | b34f13a3f03 |
12322013331203 has 4 divisors (see below), whose sum is σ = 12322035115200. Its totient is φ = 12321991547208.
The previous prime is 12322013331097. The next prime is 12322013331253. The reversal of 12322013331203 is 30213331022321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12322013331203 - 28 = 12322013330947 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12322013331253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10020275 + ... + 11182572.
It is an arithmetic number, because the mean of its divisors is an integer number (3080508778800).
Almost surely, 212322013331203 is an apocalyptic number.
12322013331203 is a deficient number, since it is larger than the sum of its proper divisors (21783997).
12322013331203 is an equidigital number, since it uses as much as digits as its factorization.
12322013331203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21783996.
The product of its (nonzero) digits is 3888, while the sum is 26.
Adding to 12322013331203 its reverse (30213331022321), we get a palindrome (42535344353524).
The spelling of 12322013331203 in words is "twelve trillion, three hundred twenty-two billion, thirteen million, three hundred thirty-one thousand, two hundred three".
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