Base | Representation |
---|---|
bin | 10001111011100101100… |
… | …000101101010000111011 |
3 | 11100210112220202202210211 |
4 | 101323211200231100323 |
5 | 130142032032000011 |
6 | 2342023042251551 |
7 | 155011225261156 |
oct | 21734540552073 |
9 | 4323486682724 |
10 | 1232211203131 |
11 | 43563a111827 |
12 | 17a989056bb7 |
13 | 8c273b0480c |
14 | 438d44c8c9d |
15 | 220bc9e5b21 |
hex | 11ee582d43b |
1232211203131 has 4 divisors (see below), whose sum is σ = 1232215306264. Its totient is φ = 1232207100000.
The previous prime is 1232211203101. The next prime is 1232211203149. The reversal of 1232211203131 is 1313021122321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1232211203131 - 223 = 1232202814523 is a prime.
It is a super-2 number, since 2×12322112031312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1232211203101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1562190 + ... + 2214691.
It is an arithmetic number, because the mean of its divisors is an integer number (308053826566).
Almost surely, 21232211203131 is an apocalyptic number.
1232211203131 is a deficient number, since it is larger than the sum of its proper divisors (4103133).
1232211203131 is an equidigital number, since it uses as much as digits as its factorization.
1232211203131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4103132.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 1232211203131 its reverse (1313021122321), we get a palindrome (2545232325452).
The spelling of 1232211203131 in words is "one trillion, two hundred thirty-two billion, two hundred eleven million, two hundred three thousand, one hundred thirty-one".
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