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12323302113 = 34107767371
BaseRepresentation
bin10110111101000011…
…01010101011100001
31011210211110121110210
423132201222223201
5200214231131423
65354455044333
7614245224333
oct133641525341
934724417423
1012323302113
115254201301
12247b0706a9
131215130a55
1484c939453
154c1d33b93
hex2de86aae1

12323302113 has 4 divisors (see below), whose sum is σ = 16431069488. Its totient is φ = 8215534740.

The previous prime is 12323302109. The next prime is 12323302157. The reversal of 12323302113 is 31120332321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12323302113 - 22 = 12323302109 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12323302113.

It is not an unprimeable number, because it can be changed into a prime (12323302183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2053883683 + ... + 2053883688.

It is an arithmetic number, because the mean of its divisors is an integer number (4107767372).

Almost surely, 212323302113 is an apocalyptic number.

It is an amenable number.

12323302113 is a deficient number, since it is larger than the sum of its proper divisors (4107767375).

12323302113 is an equidigital number, since it uses as much as digits as its factorization.

12323302113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4107767374.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 12323302113 its reverse (31120332321), we get a palindrome (43443634434).

The spelling of 12323302113 in words is "twelve billion, three hundred twenty-three million, three hundred two thousand, one hundred thirteen".

Divisors: 1 3 4107767371 12323302113