Base | Representation |
---|---|
bin | 11100000001010010111010… |
… | …100001100001000110101011 |
3 | 121011100002100102011202200211 |
4 | 130001102322201201012223 |
5 | 112123032402214132410 |
6 | 1114033023051041551 |
7 | 34646246414134003 |
oct | 3401227241410653 |
9 | 534302312152624 |
10 | 123234331005355 |
11 | 362a242815a589 |
12 | 119a37801402b7 |
13 | 539bc419c7a9b |
14 | 226080576b003 |
15 | e3a91b2a368a |
hex | 7014ba8611ab |
123234331005355 has 8 divisors (see below), whose sum is σ = 148019533225200. Its totient is φ = 98495240791776.
The previous prime is 123234331005337. The next prime is 123234331005371. The reversal of 123234331005355 is 553500133432321.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 123234331005355 - 211 = 123234331003307 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11527995685 + ... + 11528006374.
It is an arithmetic number, because the mean of its divisors is an integer number (18502441653150).
Almost surely, 2123234331005355 is an apocalyptic number.
123234331005355 is a deficient number, since it is larger than the sum of its proper divisors (24785202219845).
123234331005355 is a wasteful number, since it uses less digits than its factorization.
123234331005355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23056003133.
The product of its (nonzero) digits is 486000, while the sum is 40.
Adding to 123234331005355 its reverse (553500133432321), we get a palindrome (676734464437676).
The spelling of 123234331005355 in words is "one hundred twenty-three trillion, two hundred thirty-four billion, three hundred thirty-one million, five thousand, three hundred fifty-five".
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