Base | Representation |
---|---|
bin | 1011001101010110100001… |
… | …0111010100011010010011 |
3 | 1121122011102121000222201111 |
4 | 2303111220113110122103 |
5 | 3103404034100144403 |
6 | 42113323434114151 |
7 | 2411244336365656 |
oct | 263255027243223 |
9 | 47564377028644 |
10 | 12324012115603 |
11 | 3a21647609a41 |
12 | 147058687b957 |
13 | 6b51c319a306 |
14 | 3086b1bd189d |
15 | 1658986b556d |
hex | b35685d4693 |
12324012115603 has 8 divisors (see below), whose sum is σ = 12627821196848. Its totient is φ = 12020985041184.
The previous prime is 12324012115589. The next prime is 12324012115631. The reversal of 12324012115603 is 30651121042321.
12324012115603 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12324012115603 - 213 = 12324012107411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12324012115633) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 195469800 + ... + 195532837.
It is an arithmetic number, because the mean of its divisors is an integer number (1578477649606).
Almost surely, 212324012115603 is an apocalyptic number.
12324012115603 is a deficient number, since it is larger than the sum of its proper divisors (303809081245).
12324012115603 is an equidigital number, since it uses as much as digits as its factorization.
12324012115603 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 391003413.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 12324012115603 its reverse (30651121042321), we get a palindrome (42975133157924).
The spelling of 12324012115603 in words is "twelve trillion, three hundred twenty-four billion, twelve million, one hundred fifteen thousand, six hundred three".
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