123241434512153 has 4 divisors (see below), whose sum is σ = 123242274138240. Its totient is φ = 123240594886068.

The previous prime is 123241434512137. The next prime is 123241434512159. The reversal of 123241434512153 is 351215434142321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 123241434512153 - 2⁴ = 123241434512137 is a prime.

It is a super-2 number, since 2×123241434512153² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 123241434512153.

It is not an unprimeable number, because it can be changed into a prime (123241434512159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 419592833 + ... + 419886446.

It is an arithmetic number, because the mean of its divisors is an integer number (30810568534560).

Almost surely, 2^{123241434512153} is an apocalyptic number.

It is an amenable number.

123241434512153 is a deficient number, since it is larger than the sum of its proper divisors (839626087).

123241434512153 is an equidigital number, since it uses as much as digits as its factorization.

123241434512153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 839626086.

The product of its digits is 345600, while the sum is 41.

Adding to 123241434512153 its reverse (351215434142321), we get a palindrome (474456868654474).

The spelling of 123241434512153 in words is "one hundred twenty-three trillion, two hundred forty-one billion, four hundred thirty-four million, five hundred twelve thousand, one hundred fifty-three".