Base | Representation |
---|---|
bin | 10001111100000001100… |
… | …001111011001101011011 |
3 | 11100211202200022101010210 |
4 | 101330001201323031123 |
5 | 130144012402100233 |
6 | 2342141433542203 |
7 | 155025664015500 |
oct | 21740141731533 |
9 | 4324680271123 |
10 | 1232681284443 |
11 | 4358604a3884 |
12 | 17aa9a574963 |
13 | 8c31a31293b |
14 | 4393aad34a7 |
15 | 220e8dee163 |
hex | 11f0187b35b |
1232681284443 has 12 divisors (see below), whose sum is σ = 1911913829160. Its totient is φ = 704389305312.
The previous prime is 1232681284409. The next prime is 1232681284453. The reversal of 1232681284443 is 3444821862321.
It is not a de Polignac number, because 1232681284443 - 217 = 1232681153371 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1232681284392 and 1232681284401.
It is not an unprimeable number, because it can be changed into a prime (1232681284453) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4192793338 + ... + 4192793631.
It is an arithmetic number, because the mean of its divisors is an integer number (159326152430).
Almost surely, 21232681284443 is an apocalyptic number.
1232681284443 is a deficient number, since it is larger than the sum of its proper divisors (679232544717).
1232681284443 is an equidigital number, since it uses as much as digits as its factorization.
1232681284443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8385586986 (or 8385586979 counting only the distinct ones).
The product of its digits is 1769472, while the sum is 48.
The spelling of 1232681284443 in words is "one trillion, two hundred thirty-two billion, six hundred eighty-one million, two hundred eighty-four thousand, four hundred forty-three".
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