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1233100113 = 37311894163
BaseRepresentation
bin100100101111111…
…1001110101010001
310011221021222100120
41021133321311101
510011133200423
6322205340453
742362115030
oct11137716521
93157258316
101233100113
11583064403
122a4b67729
1316861354b
14b9aa8717
15733c7ee3
hex497f9d51

1233100113 has 16 divisors (see below), whose sum is σ = 1939623936. Its totient is φ = 681898320.

The previous prime is 1233100109. The next prime is 1233100123. The reversal of 1233100113 is 3110013321.

It is not a de Polignac number, because 1233100113 - 22 = 1233100109 is a prime.

It is a super-2 number, since 2×12331001132 = 3041071777361225538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1233100092 and 1233100101.

It is not an unprimeable number, because it can be changed into a prime (1233100103) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 946431 + ... + 947732.

It is an arithmetic number, because the mean of its divisors is an integer number (121226496).

Almost surely, 21233100113 is an apocalyptic number.

It is an amenable number.

1233100113 is a deficient number, since it is larger than the sum of its proper divisors (706523823).

1233100113 is a wasteful number, since it uses less digits than its factorization.

1233100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1894204.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 1233100113 is about 35115.5252416933. The cubic root of 1233100113 is about 1072.3406741117.

Adding to 1233100113 its reverse (3110013321), we get a palindrome (4343113434).

The spelling of 1233100113 in words is "one billion, two hundred thirty-three million, one hundred thousand, one hundred thirteen".

Divisors: 1 3 7 21 31 93 217 651 1894163 5682489 13259141 39777423 58719053 176157159 411033371 1233100113