Base | Representation |
---|---|
bin | 10001111100011101111… |
… | …011010110110111111011 |
3 | 11100212222212210110210211 |
4 | 101330131323112313323 |
5 | 130201001333312103 |
6 | 2342301013251551 |
7 | 155043540421300 |
oct | 21743573266773 |
9 | 4325885713724 |
10 | 1233157713403 |
11 | 435a85420a20 |
12 | 17abb2033bb7 |
13 | 8c394c34075 |
14 | 439840b10a7 |
15 | 22125b5d36d |
hex | 11f1ded6dfb |
1233157713403 has 12 divisors (see below), whose sum is σ = 1564897729752. Its totient is φ = 960902113920.
The previous prime is 1233157713373. The next prime is 1233157713407. The reversal of 1233157713403 is 3043177513321.
It is not a de Polignac number, because 1233157713403 - 213 = 1233157705211 is a prime.
It is a super-2 number, since 2×12331577134032 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1233157713407) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1143930550 + ... + 1143931627.
It is an arithmetic number, because the mean of its divisors is an integer number (130408144146).
Almost surely, 21233157713403 is an apocalyptic number.
1233157713403 is a deficient number, since it is larger than the sum of its proper divisors (331740016349).
1233157713403 is a wasteful number, since it uses less digits than its factorization.
1233157713403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2287862202 (or 2287862195 counting only the distinct ones).
The product of its (nonzero) digits is 158760, while the sum is 40.
The spelling of 1233157713403 in words is "one trillion, two hundred thirty-three billion, one hundred fifty-seven million, seven hundred thirteen thousand, four hundred three".
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