Base | Representation |
---|---|
bin | 111001011011100111… |
… | …1010111001110110011 |
3 | 102210100022102221021102 |
4 | 1302313033113032303 |
5 | 4010041313422011 |
6 | 132354125315015 |
7 | 11624213053016 |
oct | 1626717271663 |
9 | 383308387242 |
10 | 123333342131 |
11 | 4833a50242a |
12 | 1baa0105a6b |
13 | b82697196c |
14 | 5d7dd2137d |
15 | 331c94273b |
hex | 1cb73d73b3 |
123333342131 has 4 divisors (see below), whose sum is σ = 123343033392. Its totient is φ = 123323650872.
The previous prime is 123333342079. The next prime is 123333342149. The reversal of 123333342131 is 131243333321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 123333342131 - 222 = 123329147827 is a prime.
It is a super-2 number, since 2×1233333421312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 123333342094 and 123333342103.
It is not an unprimeable number, because it can be changed into a prime (123333344131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4826516 + ... + 4852001.
It is an arithmetic number, because the mean of its divisors is an integer number (30835758348).
Almost surely, 2123333342131 is an apocalyptic number.
123333342131 is a deficient number, since it is larger than the sum of its proper divisors (9691261).
123333342131 is an equidigital number, since it uses as much as digits as its factorization.
123333342131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9691260.
The product of its digits is 11664, while the sum is 29.
Adding to 123333342131 its reverse (131243333321), we get a palindrome (254576675452).
The spelling of 123333342131 in words is "one hundred twenty-three billion, three hundred thirty-three million, three hundred forty-two thousand, one hundred thirty-one".
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