Base | Representation |
---|---|
bin | 10110111110011110… |
… | …01110011101011001 |
3 | 1011211122221101020022 |
4 | 23133033032131121 |
5 | 200230310321040 |
6 | 5400003040225 |
7 | 614451565556 |
oct | 133717163531 |
9 | 34748841208 |
10 | 12335245145 |
11 | 525aa19283 |
12 | 2483070075 |
13 | 1217752b32 |
14 | 850367a2d |
15 | 4c2de26b5 |
hex | 2df3ce759 |
12335245145 has 4 divisors (see below), whose sum is σ = 14802294180. Its totient is φ = 9868196112.
The previous prime is 12335245133. The next prime is 12335245147. The reversal of 12335245145 is 54154253321.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2117472256 + 10217772889 = 46016^2 + 101083^2 .
It is a cyclic number.
It is not a de Polignac number, because 12335245145 - 210 = 12335244121 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12335245147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1233524510 + ... + 1233524519.
It is an arithmetic number, because the mean of its divisors is an integer number (3700573545).
Almost surely, 212335245145 is an apocalyptic number.
It is an amenable number.
12335245145 is a deficient number, since it is larger than the sum of its proper divisors (2467049035).
12335245145 is an equidigital number, since it uses as much as digits as its factorization.
12335245145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2467049034.
The product of its digits is 72000, while the sum is 35.
Adding to 12335245145 its reverse (54154253321), we get a palindrome (66489498466).
The spelling of 12335245145 in words is "twelve billion, three hundred thirty-five million, two hundred forty-five thousand, one hundred forty-five".
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