12340021433 has 4 divisors (see below), whose sum is σ = 12876544128. Its totient is φ = 11803498740.

The previous prime is 12340021381. The next prime is 12340021459. The reversal of 12340021433 is 33412004321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12340021433 - 2¹⁰ = 12340020409 is a prime.

It is a super-2 number, since 2×12340021433² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (23), and also a Moran number because the ratio is a prime number: 536522671 = 12340021433 / (1 + 2 + 3 + 4 + 0 + 0 + 2 + 1 + 4 + 3 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12340021399 and 12340021408.

It is not an unprimeable number, because it can be changed into a prime (12340021493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 268261313 + ... + 268261358.

It is an arithmetic number, because the mean of its divisors is an integer number (3219136032).

Almost surely, 2^12340021433 is an apocalyptic number.

It is an amenable number.

12340021433 is a deficient number, since it is larger than the sum of its proper divisors (536522695).

12340021433 is an equidigital number, since it uses as much as digits as its factorization.

12340021433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 536522694.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 12340021433 its reverse (33412004321), we get a palindrome (45752025754).

The spelling of 12340021433 in words is "twelve billion, three hundred forty million, twenty-one thousand, four hundred thirty-three".