Base | Representation |
---|---|
bin | 11100000011101111000101… |
… | …000110010101100111101001 |
3 | 121011221010011101211201020101 |
4 | 130003233011012111213221 |
5 | 112133304310102414340 |
6 | 1114242033552025401 |
7 | 34664333620315411 |
oct | 3403570506254751 |
9 | 534833141751211 |
10 | 123402012154345 |
11 | 36357554860661 |
12 | 11a10178232261 |
13 | 53b19b5409582 |
14 | 2268991469641 |
15 | e3ee82256c9a |
hex | 703bc51959e9 |
123402012154345 has 16 divisors (see below), whose sum is σ = 156990598207488. Its totient is φ = 92954959456320.
The previous prime is 123402012154319. The next prime is 123402012154363. The reversal of 123402012154345 is 543451210204321.
It is not a de Polignac number, because 123402012154345 - 243 = 114605919132137 is a prime.
It is a super-2 number, since 2×1234020121543452 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (37).
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10758670129 + ... + 10758681598.
It is an arithmetic number, because the mean of its divisors is an integer number (9811912387968).
Almost surely, 2123402012154345 is an apocalyptic number.
It is an amenable number.
123402012154345 is a deficient number, since it is larger than the sum of its proper divisors (33588586053143).
123402012154345 is a wasteful number, since it uses less digits than its factorization.
123402012154345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21517351800.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 123402012154345 its reverse (543451210204321), we get a palindrome (666853222358666).
The spelling of 123402012154345 in words is "one hundred twenty-three trillion, four hundred two billion, twelve million, one hundred fifty-four thousand, three hundred forty-five".
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