Base | Representation |
---|---|
bin | 10110111111001010… |
… | …01100100101100011 |
3 | 1011212001202222210001 |
4 | 23133211030211203 |
5 | 200233244122033 |
6 | 5400330320431 |
7 | 614551544242 |
oct | 133745144543 |
9 | 34761688701 |
10 | 12341004643 |
11 | 52631a24a0 |
12 | 2484b89117 |
13 | 12189bb516 |
14 | 851026959 |
15 | 4c367de7d |
hex | 2df94c963 |
12341004643 has 4 divisors (see below), whose sum is σ = 13462914168. Its totient is φ = 11219095120.
The previous prime is 12341004619. The next prime is 12341004647. The reversal of 12341004643 is 34640014321.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34640014321 = 11 ⋅3149092211.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12341004643 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12341004647) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 560954746 + ... + 560954767.
It is an arithmetic number, because the mean of its divisors is an integer number (3365728542).
Almost surely, 212341004643 is an apocalyptic number.
12341004643 is a deficient number, since it is larger than the sum of its proper divisors (1121909525).
12341004643 is a wasteful number, since it uses less digits than its factorization.
12341004643 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1121909524.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 12341004643 its reverse (34640014321), we get a palindrome (46981018964).
The spelling of 12341004643 in words is "twelve billion, three hundred forty-one million, four thousand, six hundred forty-three".
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