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1234414523353 = 11112219502123
BaseRepresentation
bin10001111101101000110…
…101101101001111011001
311101000020110201000221111
4101331220311231033121
5130211040104221403
62343025431140321
7155116641216244
oct21755065551731
94330213630844
101234414523353
1143656a8a9930
1217b2a2b146a1
138c5354294ab
1443a62d8c25b
152219b16b56d
hex11f68d6d3d9

1234414523353 has 4 divisors (see below), whose sum is σ = 1346634025488. Its totient is φ = 1122195021220.

The previous prime is 1234414523351. The next prime is 1234414523359. The reversal of 1234414523353 is 3533254144321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1234414523353 - 21 = 1234414523351 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1234414523351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56109751051 + ... + 56109751072.

It is an arithmetic number, because the mean of its divisors is an integer number (336658506372).

Almost surely, 21234414523353 is an apocalyptic number.

It is an amenable number.

1234414523353 is a deficient number, since it is larger than the sum of its proper divisors (112219502135).

1234414523353 is a wasteful number, since it uses less digits than its factorization.

1234414523353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 112219502134.

The product of its digits is 518400, while the sum is 40.

Adding to 1234414523353 its reverse (3533254144321), we get a palindrome (4767668667674).

The spelling of 1234414523353 in words is "one trillion, two hundred thirty-four billion, four hundred fourteen million, five hundred twenty-three thousand, three hundred fifty-three".

Divisors: 1 11 112219502123 1234414523353