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12350253035 = 52470050607
BaseRepresentation
bin10111000000010000…
…11110011111101011
31011212201011212012002
423200020132133223
5200243131044120
65401300441215
7615023263421
oct134010363753
934781155162
1012350253035
11526843999a
1224880a920b
13121a8a8c43
14852353111
154c43a9375
hex2e021e7eb

12350253035 has 4 divisors (see below), whose sum is σ = 14820303648. Its totient is φ = 9880202424.

The previous prime is 12350253001. The next prime is 12350253053. The reversal of 12350253035 is 53035205321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12350253035 - 28 = 12350252779 is a prime.

It is a super-2 number, since 2×123502530352 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12350252989 and 12350253007.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1235025299 + ... + 1235025308.

It is an arithmetic number, because the mean of its divisors is an integer number (3705075912).

Almost surely, 212350253035 is an apocalyptic number.

12350253035 is a deficient number, since it is larger than the sum of its proper divisors (2470050613).

12350253035 is an equidigital number, since it uses as much as digits as its factorization.

12350253035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2470050612.

The product of its (nonzero) digits is 13500, while the sum is 29.

Adding to 12350253035 its reverse (53035205321), we get a palindrome (65385458356).

The spelling of 12350253035 in words is "twelve billion, three hundred fifty million, two hundred fifty-three thousand, thirty-five".

Divisors: 1 5 2470050607 12350253035