Base | Representation |
---|---|
bin | 10111000000011110… |
… | …01100000001110011 |
3 | 1011212211111020120212 |
4 | 23200033030001303 |
5 | 200244103344103 |
6 | 5401402254335 |
7 | 615044241653 |
oct | 134017140163 |
9 | 34784436525 |
10 | 12352012403 |
11 | 5269430815 |
12 | 24887b73ab |
13 | 121b0739a3 |
14 | 852690363 |
15 | 4c46057d8 |
hex | 2e03cc073 |
12352012403 has 4 divisors (see below), whose sum is σ = 12750464448. Its totient is φ = 11953560360.
The previous prime is 12352012381. The next prime is 12352012447. The reversal of 12352012403 is 30421025321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12352012403 - 230 = 11278270579 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12352012103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 199225976 + ... + 199226037.
It is an arithmetic number, because the mean of its divisors is an integer number (3187616112).
Almost surely, 212352012403 is an apocalyptic number.
12352012403 is a deficient number, since it is larger than the sum of its proper divisors (398452045).
12352012403 is an equidigital number, since it uses as much as digits as its factorization.
12352012403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 398452044.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 12352012403 its reverse (30421025321), we get a palindrome (42773037724).
The spelling of 12352012403 in words is "twelve billion, three hundred fifty-two million, twelve thousand, four hundred three".
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