123525513113441 has 4 divisors (see below), whose sum is σ = 123526395244692. Its totient is φ = 123524630982192.

The previous prime is 123525513113363. The next prime is 123525513113447. The reversal of 123525513113441 is 144311315525321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 45882469795600 + 77643043317841 = 6773660^2 + 8811529^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-123525513113441 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (123525513113447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 440855546 + ... + 441135651.

It is an arithmetic number, because the mean of its divisors is an integer number (30881598811173).

Almost surely, 2^{123525513113441} is an apocalyptic number.

It is an amenable number.

123525513113441 is a deficient number, since it is larger than the sum of its proper divisors (882131251).

123525513113441 is an equidigital number, since it uses as much as digits as its factorization.

123525513113441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 882131250.

The product of its digits is 216000, while the sum is 41.

Adding to 123525513113441 its reverse (144311315525321), we get a palindrome (267836828638762).

The spelling of 123525513113441 in words is "one hundred twenty-three trillion, five hundred twenty-five billion, five hundred thirteen million, one hundred thirteen thousand, four hundred forty-one".