123531543011035 has 4 divisors (see below), whose sum is σ = 148237851613248. Its totient is φ = 98825234408824.

The previous prime is 123531543011021. The next prime is 123531543011053. The reversal of 123531543011035 is 530110345135321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 123531543011035 - 2¹³ = 123531543002843 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 123531543010985 and 123531543011003.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12353154301099 + ... + 12353154301108.

It is an arithmetic number, because the mean of its divisors is an integer number (37059462903312).

Almost surely, 2^{123531543011035} is an apocalyptic number.

123531543011035 is a deficient number, since it is larger than the sum of its proper divisors (24706308602213).

123531543011035 is an equidigital number, since it uses as much as digits as its factorization.

123531543011035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24706308602212.

The product of its (nonzero) digits is 81000, while the sum is 37.

Adding to 123531543011035 its reverse (530110345135321), we get a palindrome (653641888146356).

The spelling of 123531543011035 in words is "one hundred twenty-three trillion, five hundred thirty-one billion, five hundred forty-three million, eleven thousand, thirty-five".